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AngularJS GET ajax request with PHP (Fetching data)
September 11, 2014

In this tutorial, i will be explaining how to fetch data from the mysql database via angularjs via GET ajax call. I will be using angularjs \$http service to get data from the mysql database with php. Note: create a mysql database, with students table having two fields Name(varchar), Roll(int). Also insert some values. Copy the following contents to their respective file & you are done.

index.html

<!DOCTYPE html>
<html ng-app="fetch">
<head>
<title>AngularJS GET request with PHP</title>
 <link rel="stylesheet" href="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
       <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.24/angular.min.js"></script>
</head>

<body>
<br>
 <div class="row">
   <div class="container">
     <h1>Angular $http GET Ajax Call</h1>
     <div ng-controller="dbCtrl">
     <input type="text" ng-model="searchFilter" class="form-control">
        <table class="table table-hover">
            <thead>
                <tr>
                    <th>Name</th>
                    <th>Roll No</th>
                </tr>
            </thead>
            <tbody>
                <tr ng-repeat="students in data | filter:searchFilter">
                    <td>{{students.Name}}</td>
                    <td>{{students.Roll}}</td>
                </tr>
            </tbody>
        </table>
     </div>
   </div>
 </div>
</body>

<script>
    var fetch = angular.module('fetch', []);

    fetch.controller('dbCtrl', ['$scope', '$http', function ($scope, $http) {
        $http.get("fetch.php")
            .success(function(data){
                $scope.data = data;
            })
            .error(function() {
                $scope.data = "error in fetching data";
            });
    }]);

</script>

</html>

fetch.php

<?php
//database settings
$connect = mysqli_connect("hostname", "username", "password", "dbname");

$result = mysqli_query($connect, "select * from students");

$data = array();

while ($row = mysqli_fetch_array($result)) {
  $data[] = $row;
}
    print json_encode($data);
 ?>